[Rd] replicating lists
Wed, 11 Apr 2001 16:14:04 +0100 (BST)
On Wed, 11 Apr 2001, David James wrote:
> Yes, I agree that the work-around needs some care, but I'm not sure
> we need to wrap the list itself -- we're simply using properties of
> "[" on lists. If the subscript is rep(1, 10), then we'll get the
> first element 10 times (which is *not* replicating the list).
> To get the replication we need to index every element in
> the list as many times as required.
Not sure I follow you here. I want n copies of an arbitrary list, as a
list, so list(fred)[rep(1, n)] is desired, where fred is the list I want
replicated. Unfortuntely this does not solve the underlying problem,
which is that I want to do
> tmp <- array(fred, c(3, 4))
which breaks because "rep", invoked by "array", currently fails to handle
complex lists. However I am happy to report that
> tmp <- array(list(fred)[rep(1, 12)], c(3, 4))
does work as expected:
> tmp[[3, 4]] # fred again!
So that's the work-around in my particular case.
Jonathan Rougier Science Laboratories
Department of Mathematical Sciences South Road
University of Durham Durham DH1 3LE
tel: +44 (0)191 374 2361, fax: +44 (0)191 374 7388
r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !) To: firstname.lastname@example.org