[Rd] base::mean not consistent about NA/NaN

[Ista Zahn]

The current behavior is as documented. See ?NA, which says

"Numerical computations using ‘NA’ will normally result in ‘NA’: a
     possible exception is where ‘NaN’ is also involved, in which case
     either might result"

--Ista

On Mon, Jul 2, 2018 at 11:25 AM, Jan Gorecki <j.gorecki using wit.edu.pl> wrote:
> Hi,
> base::mean is not consistent in terms of handling NA/NaN.
> Mean should not depend on order of its arguments while currently it is.
>
>     mean(c(NA, NaN))
>     #[1] NA
>     mean(c(NaN, NA))
>     #[1] NaN
>
> I created issue so in case of no replies here status of it can be looked up
> at:
> https://bugs.r-project.org/bugzilla/show_bug.cgi?id=17441
>
> Best,
> Jan
>
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>
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