[Rd] detect ->
du@@@@dr|@n @end|ng |rom gm@||@com
Mon Apr 13 10:39:11 CEST 2020
Thank you for your replies, this actually has little to do with the regular R code but more to signal what in my package QCA is referred to as a necessity relation A <- B (A is necessary for B) and sufficiency A -> B (A is sufficient for B).
If switched by the parser, A -> B becomes B <- A which makes B necessary for A, while the intention is to signal sufficiency for B.
Capturing in a quoted string is trivial, but I am now experimenting with substitute() to allow unquoted expressions.
This is especially useful when selecting A and B from the columns of a data frame, using: c(A, B) instead of c("A", "B") with a lot more quotes for more complex expressions using more columns.
I would be grateful for any pointer to a project that processes the code while it is still raw text. I could maybe learn from their code and adapt to my use case.
> On 13 Apr 2020, at 11:23, Gabriel Becker <gabembecker using gmail.com> wrote:
> Indeed, this has come up in a few places, but as Gabor says, there is no such thing as right hand assignment at any point after parsing is complete.
> This means the only feasible way to detect it, which a few projects do I believe, is process the code while it is still raw text, before it goes into the parser, and have clever enough regular expressions.
> The next question, then, is why are you trying to detect right assignment. Doing so can be arguably useful fo linting, its true. Otherwise, though, because its not really a "real thing" when the R code is being executed, its not something thats generally meaningful to detect in most cases.
> On Mon, Apr 13, 2020 at 12:52 AM Gábor Csárdi <csardi.gabor using gmail.com> wrote:
> That parser already flips -> to <- before creating the parse tree.
> On Mon, Apr 13, 2020 at 8:39 AM Adrian Dușa <dusa.adrian using gmail.com> wrote:
> > I searched and tried for hours, to no avail although it looks simple.
> > (function(x) substitute(x))(A <- B)
> > #A <- B
> > (function(x) substitute(x))(A -> B)
> > # B <- A
> > In the first example, A occurs on the LHS, but in the second example A is somehow evaluated as if it occured on the RHS, despite my understanding that substitute() returns the unevaluated parse tree.
> > Is there any way, or is it even possible to detect the right hand assignment, to determine whether A occurs on the LHS?
> > Thanks in advance for any hint,
> > Adrian
> > —
> > Adrian Dusa
> > University of Bucharest
> > Romanian Social Data Archive
> > Soseaua Panduri nr. 90-92
> > 050663 Bucharest sector 5
> > Romania
> > https://adriandusa.eu
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