[R] Histogram for factors

[Peter Dalgaard BSA]

Thomas Vogels <tov at ece.cmu.edu> writes:

> Hi,
> 
> I keep running into this:
> R> hist (f)
> Error in hist.default(f) : `x' must be numeric
> 
> To which of course something like (simplified but not beyond repair):
> R> hist.factor <- function (ff) {
>   jj <- table (ff)
>   jb <- barplot (jj, ylab="Frequency", xlab=deparse(substitute(ff)))
>   axis (1, jb, names (jj))
> }
> R> hist (f)
> is a possible solution.
> 
> Why is a 'hist.factor' not part of the base distribution?  Is this
> kind of thing discouraged?  Usually not needed?  Am I missing sth else?

Well histograms are density estimates defined for continuous
variables. What you're drawing is a barplot. barplot.factor might be a
good idea, though.

-- 
   O__  ---- Peter Dalgaard             Blegdamsvej 3  
  c/ /'_ --- Dept. of Biostatistics     2200 Cph. N   
 (*) \(*) -- University of Copenhagen   Denmark      Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk)             FAX: (+45) 35327907
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._