[R] substitute values in a vector,dataframe

Prof Brian D Ripley ripley at stats.ox.ac.uk
Thu May 31 10:46:29 CEST 2001


On Thu, 31 May 2001, Frank Gerrit Zoellner wrote:

> Hi!
>
> I've got a dataframe with -Inf values inside and i want to substitute
them with 0. The dataframe is only one column. How can I do this in R?

df[df[, 1] %in% -Inf, 1] <- 0

as in

df <- data.frame(a=c(1:3, -Inf, 4))
df[df[, 1] %in% -Inf, 1] <- 0
df
  a
1 1
2 2
3 3
4 0
5 4

If there were more than one column, use lapply.


-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272860 (secr)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._



More information about the R-help mailing list