[R] More on for() Loop...

[Frank E Harrell Jr]

On Sat, 8 Jun 2002 22:44:07 +1200 (NZST)
Ko-Kang Kevin Wang <kwan022 at stat.auckland.ac.nz> wrote:

> Hi,
> 
> Say I want to do something like fitting 10 different sized trees with
> rpart() function.  The only modification I need to do is to set 10
> different cp's, which I have in a vector called foo.
> 
> Can I do something like:
> 
> for(i in 1:10) {
>   rpart(y ~ ., cp = foo[i], data = mydata)
> }
> 
> My problem is, I wish to save the 10 rpart objects into 10 different
> names, my.rpart1 ~ my.rpart10, for example.  But I'm not sure how to do
> this...
> 

fits <- vector('list',10)
names(fits) <- format(foo)  # optional - will label list components
for(i in 1:10) fits[[i]] <- rpart(...)

Fetch the ith fit by using fits[[i]] (or fits[['formatted cp value']]).

-Frank Harrell

> 
> Cheers,
> 
> Kevin
> 
> ------------------------------------------------------------------------------
> Ko-Kang Kevin Wang
> Postgraduate PGDipSci Student
> Department of Statistics
> University of Auckland
> New Zealand
> 
> Homepage: http://www.stat.auckland.ac.nz/~kwan022
> 
> E-mail: kwan022 at stat.auckland.ac.nz
> 
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-- 
Frank E Harrell Jr              Prof. of Biostatistics & Statistics
Div. of Biostatistics & Epidem. Dept. of Health Evaluation Sciences
U. Virginia School of Medicine  http://hesweb1.med.virginia.edu/biostat
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