[R] aov/glm

RenE J.V. Bertin rjvbertin at hotmail.com
Thu Jun 27 17:57:42 CEST 2002


This is an "intuition" question from a "stats-user!=expert". I hope this is 
the right place to post it!

I understand that lm() is quite sensitive to data with severe outliers. I 
imagine therefore that aov(), which uses lm(), is too. I have tried to hack 
aov() such that it calls rlm() which is much more robust against outliers. 
Even though the calling conventions for lm() and rlm() are quite similar, 
this just doesn't work:
Error in terms.default(formula, data = data) :
	no terms component

1) Is such a modification feasible, and does it make sense to use rlm() (or 
similar) in an anova?
2) How to do this, or is there already such a function?

Thanks in advance,

RenE J.V. Bertin
College de France/LPPA
11, place Marcelin Berthelot
75005 Paris, France


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