[R] Breakdown of Treatment Sum of Squares

[Wendy Catchpole]

When using an ordered factor in aov, how do I break the treatment sum of 
squares
into all its separate degrees of freedom? In other words can I use contr.poly
in aov to get the full breakdown of the treatment sum of squares?

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._