[R] Spearman rank-order correlation matrix

[Russell Senior]

I"ve got a data frame with a selection of columns I want to compute a
rank-order correlation matrix from without disturbing the original
data frame.

  foo[,c("a","b","d","f","g")]

What I wanted to do, intuitively, was:

  > cor(rank(foo[,c("a","b","d","f","g")]))

but rank in that context ranks all of the values from the matrix
together as one long vector.  I want the columns (and their names) to
be preserved, just replacing the value with its rank.  What is the
most direct way to get what I want?

Thanks!

-- 
Russell Senior         ``The two chiefs turned to each other.        
seniorr at aracnet.com      Bellison uncorked a flood of horrible       
                         profanity, which, translated meant, `This is
                         extremely unusual.' ''                      
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