[R] lm with an arbitrary number of terms

[Bill.Venables@csiro.au]

What are you using the data frame argument for?

If y, x1, x2, ..., xn were all the variables in the data frame all you need
do is

myfun <- function(y, dat) {
	lm(y ~ ., dat) 
}

but your question is very vague and ill-posed.


-----Original Message-----
From: Richard Nixon [mailto:richard.nixon at mrc-bsu.cam.ac.uk]
Sent: Thursday, April 03, 2003 2:50 AM
To: r-help at stat.math.ethz.ch
Subject: [R] lm with an arbitrary number of terms 


Hello folks,

Any ideas how to do this?

data.frame is a data frame with column names "x1",...,"xn"
y is a response variable of length dim(data.frame)[1]

I want to write a function

function(y, data.frame){
    lm(y~x1+...+xn)
}

This would be easy if n was always the same.
If n is arbitrary how could I feed the x1+...+xn terms into
lm(response~terms)?

Thanks
Richard

--
Dr. Richard Nixon
MRC Biostatistics Unit, Cambridge, UK
http://www.mrc-bsu.cam.ac.uk/personal/richard
Tel: +44 (0)1223 330382, Fax: +44 (0)1223 33038

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