# [R] question about if else

Liaw, Andy andy_liaw at merck.com
Fri Feb 27 20:05:33 CET 2004

```You need to (re-)read ?ifelse.  In ifelse(L, v1, v2), L is suppose to be a
vector of logicals (or an expression that evaluates to one), and v1 and v2
are vectors of same length as L; i.e., ifelse() vectorizes if ... else ....
In the first case:

r = ifelse(length(c())!=0, c(), c(1,2))

length(c()) != 0 is FALSE, so you just get 1 as the answer.  In the second
case,

r = ifelse(length(c())==0, c(), c(1,2))

length(c()) == 0 is TRUE, so ifelse tries to return the first element of
c(), which does not exist.

I suspect you really want if ... else ....

Andy

> From: Svetlana Eden
>
> Today is a good day for asking question, I guess.
>
> > c()
> NULL
> >
> > length(c())==0
> [1] TRUE
> >
> > r = ifelse(length(c())!=0, c(), c(1,2))  ### OK
> > r = c()                                  ### OK
> > r = ifelse(length(c())==0, c(), c(1,2))  ### why this is
> not OK (given
> > the previous two)?
> Error in "[<-"(`*tmp*`, test, value = rep(yes, length =
> length(ans))[test]) :
>         incompatible types
> >
> > c() == NULL
> logical(0)
> >
> > r = ifelse(c()==NULL, c(), c(1,2))       ### why this line does not
> > r                                        ### result in error -
> logical(0)                                 ### 'c()==NULL' is not TRUE
> and not FALSE ?
> >
> >
>
> --
> Svetlana Eden        Biostatistician II            School of Medicine
>                      Department of Biostatistics   Vanderbilt
> University
>
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