[R] Problem with the grep function
Marc Mamin
M.Mamin at intershop.de
Fri Jul 9 10:55:19 CEST 2004
Hi,
you can use regular expression with grep.
For example:
>exactmatch<-function(s,l){return(grep(paste('^',s,'$',sep=''),l))}
>t<-c('a','ab','abc','c','ca','ab')
> exactmatch('ab',t)
[1] 2 6
HTH
Marc
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Petr Pikal
Sent: Thursday, July 08, 2004 2:28 PM
To: aubert at inapg.fr; r-help at stat.math.ethz.ch
Subject: Re: [R] Problem with the grep function
Hi
You can use %in%
> nom%in%"b"
[1] FALSE TRUE FALSE
which gives you a logical vector of exact matches
> (1:3)[nom%in%"b"]
[1] 2
or charmatch
> charmatch("b",nom)
[1] 2
> charmatch("ab",nom)
[1] 3
if you expect only one exact match.
But I expect someone can give you better answer.
Cheers
Petr
On 8 Jul 2004 at 9:20, aubert at inapg.fr wrote:
> Let me present to you my problem :
>
> I have a character vector x and I would like to obtain the indices of
> the elements of this vector that yielded exactly a match.
>
> For example, x=nom, pattern="b", I would to obtain 2 because "b" is
> on the second position.
>
> First program :
> nom <- c("a","b","ab")
> grep("b",nom)
> 2 3
>
> Then I try the option extended =FALSE (instead of TRUE by default) and
> I obtain '2 3' a second time.
>
> Please can you help me : How can I obtain only 2 in using the grep
> function (without using the match function).
>
> Thanks you
>
> Julie AUBERT
>
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Petr Pikal
petr.pikal at precheza.cz
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