# [R] merging with aggregating

Marc Schwartz MSchwartz at mn.rr.com
Tue Dec 6 15:11:10 CET 2005

```On Tue, 2005-12-06 at 14:22 +0100, Dubravko Dolic wrote:
> Dear List,
>
> I have two data.frame of the following form:
>
> A:
>
> n  V1 V2
> 1  12  0
> 2  10  8
> 3   3  8
> 4   8  4
> 6   7  3
> 7  12  0
> 8   1  0
> 9  18  0
> 10  1  0
> 13  2  0
>
> B:
>
> n  V1 V2
> 1   0  2
> 2   0  3
> 3   1  9
> 4  12  8
> 5   2  9
> 6   2  9
> 8   2  0
> 10  4  1
> 11  7  1
> 12  0  1
>
>
> Now I want to merge those frame to one data.frame with summing up the
> columns V1 and V2 but not the column n. So the result in this example
> would be:
>
> AB:
>
> n  V1 V2
> 1  12  2
> 2  10 11
> 3   4 17
> 4  20 12
> 5   2  9
> 6   9 12
> 7  12  0
> 8   3  0
> 9  18  0
> 10  5  1
> 11  7  1
> 12  0  1
> 13  2  0
>
>
> So Columns V1 and V2 are the sum of A und B while n has its old value.
> Notice that there are different rows in n of A and B.
>
> I don't have a clue how to start here. Any hint is welcome.
>
> Thanks

There might be a somewhat easier way, but here is one approach:

# Use merge() to join A and B on 'n'
# Set all = TRUE to include non-matched rows

> C <- merge(A, B, by = "n", all = TRUE)

> C
n V1.x V2.x V1.y V2.y
1   1   12    0    0    2
2   2   10    8    0    3
3   3    3    8    1    9
4   4    8    4   12    8
5   5   NA   NA    2    9
6   6    7    3    2    9
7   7   12    0   NA   NA
8   8    1    0    2    0
9   9   18    0   NA   NA
10 10    1    0    4    1
11 11   NA   NA    7    1
12 12   NA   NA    0    1
13 13    2    0   NA   NA

# Now get the rowSums() for the V1/V2 column pairs
# and create a new dataframe from the
# results

> AB <- data.frame(n = C\$n,
V1 = rowSums(C[, c(2, 4)], na.rm = TRUE),
V2 = rowSums(C[, c(3, 5)], na.rm = TRUE))

> AB
n V1 V2
1   1 12  2
2   2 10 11
3   3  4 17
4   4 20 12
5   5  2  9
6   6  9 12
7   7 12  0
8   8  3  0
9   9 18  0
10 10  5  1
11 11  7  1
12 12  0  1
13 13  2  0