[R] Puzzled in utilising summary.lm() to obtain Var(x)

Gabor Grothendieck ggrothendieck at gmail.com
Wed Jun 15 05:52:56 CEST 2005


On 6/14/05, Ajay Narottam Shah <ajayshah at mayin.org> wrote:
> > > I have a program which is doing a few thousand runs of lm(). Suppose
> > > it is a simple model
> > >   y = a + bx1 + cx2 + e
> > >
> > > I have the R object "d" where
> > >   d <- summary(lm(y ~ x1 + x2))
> > >
> > > I would like to obtain Var(x2) out of "d". How might I do it?
> > >
> > > I can, of course, always do sd(x2). But it would be much more
> > > convenient if I could snoop around the contents of summary.lm and
> > > extract Var() out of it. I couldn't readily see how. Would you know
> > > what would click?
> >
> > Is the question how to get the variance of a column of the
> > model matrix for a model that is the sum of terms given only
> > summary output and the column name but not the name of the
> > data frame?  If that is it then try this:
> >
> > d <- summary(lm(Sepal.Length ~ Sepal.Width, iris)) # test data
> > var(model.matrix(eval(d$call))[,"Sepal.Width"])
> 
> Yes, this is indeed exactly what I was looking for :-) Thanks,
> 
> The eval() pays the full cost of running d$call?

Yes. It reruns it.  If we can assume that the second arg to lm is data=
then we could do this which simply grabs the indicated column from
the data frame:

f <- function(d, name) eval(substitute(with(eval(d$call[[3]]), name)))
f(d, Sepal.Width)  # same as iris$Sepal.Width

# or

f <- function(d, charname) eval(d$call[[3]])[[charname]]
f(d, "Sepal.Width")




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