[R] force apply() to return a list

[Robin Hankin]

Hi Gabor

thanks for this.


On 21 Nov 2005, at 13:26, Gabor Grothendieck wrote:
> Try this:
>
> tapply(a, row(a), f, simplify = FALSE)
>

[
here
a <- cbind(1:5 , 5:1)
f <- function(x){list(1:max(x[1],4))}
]


This also works.  I actually  need unlist(... , recursive=FALSE)
to pass the list to do.call() but that 's fine.

But,  my question here is: how does one arrive at
such a solution from the manpage?  The manpage seems
to indicate that the first argument to tapply() is a ragged
array, or a vector.

I can't reconcile Gabor's  use of  tapply() with the manpage.

How to  understand Gabor's suggestion better?








>>

--
Robin Hankin
Uncertainty Analyst
National Oceanography Centre, Southampton
European Way, Southampton SO14 3ZH, UK
  tel  023-8059-7743