[R] dynamic lists (data frames?)

[tom wright]

Got it thanks
the trick was to create a variable with the new name
str_idx<-paste('c',i,sep='')
then use double square brackets
l_cooef[str_idx]]<-whatever()


f_haardisolve<-function(v_dataset){
    #pad data to make length a power of 2
    v_dataset<-f_paddata(v_dataset)

    l_cooef<-list() #holder for cooefficents
    i_count<-1      #identity counter

    while(length(v_dataset)>0){
        #seperate odd and even points
        v_dataset<-f_splitpoints(v_dataset)

        v_dataset<-f_haarpredict(v_dataset)
        v_dataset<-f_haaruplift(v_dataset)
        
        str_idx<-paste('c',i_count,sep='')
        l_cooef[[str_idx]]<-list()

l_cooef[[str_idx]]<-v_dataset[c((length(v_dataset)/2)+1:(length(v_dataset)/2))]
        v_dataset<-v_dataset[c(1:length(v_dataset)/2)]

        i_count<-i_count+1
    }
    l_cooef
}


On Tue, 2005-27-09 at 10:39 -0400, tom wright wrote:
> Can someone please show me what I need to get something like this to
> work
> 
> for(a in c(1:5)){
> 	data$a<-c(a:10)
> }
> 
> so that i end up with a structure
> data$1<-[1,2,3,4,5,6,7,8,9,10]
> data$2<-[2,3,4,5,67,8,9,10]
> data$3<-[3,4,5,67,8,9,10]
> data$4<-[4,5,67,8,9,10]
> data$5<-[5,67,8,9,10]
> 
> thanks loads
> Tom
> 
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