[R] apply(table) miss factor structure

Dimitris Rizopoulos dimitris.rizopoulos at med.kuleuven.be
Wed Apr 19 16:08:51 CEST 2006


you should use:

lapply(restr[c("p1","p2")], table)


I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://www.med.kuleuven.be/biostat/
     http://www.student.kuleuven.be/~m0390867/dimitris.htm


----- Original Message ----- 
From: "Cézar Freitas" <cafanselmo12 at yahoo.com.br>
To: <r-help at stat.math.ethz.ch>
Sent: Wednesday, April 19, 2006 3:50 PM
Subject: [R] apply(table) miss factor structure


> Hi, all.
> I didn't find something similar to this problem in
> past list.
>
> I have a data frame (named restr) where some columns
> are factors, like you can see:
>
>> table(restr[,"p1"])
> 0  1  2  3  4  5
> 0 26  1  0  1  0
>> table(restr[,"p2"])
> 0  1  2  3  4  5  6
> 0 13 11  1  2  1  0
>
> When I use apply, the factor structure is missed:
>
>> apply(restr[,c("p1","p2")], 2, table)
> $p1
>
> 1  2  4
> 26  1  1
>
> $p2
>
> 1  2  3  4  5
> 13 11  1  2  1
>
> Can I use a matricial (like apply) manner to do this
> holding the factor structure (the zero-counts must be
> displayed)?
>
> Thanks,
> Cezar Freitas
> Unicamp - Brasil
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! 
> http://www.R-project.org/posting-guide.html
> 


Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm




More information about the R-help mailing list