[R] creating a data frame from a list

[Gabor Grothendieck]

Create a zoo object from each component of lst
using the names as the "times".   Then merge
them together using merge.zoo, set the rownames
from the times and extract out the data:

library(zoo)
z <- do.call(merge, lapply(lst, function(x) zoo(x, names(x))))
rownames(z) <- time(z)
coredata(z)


On 7/5/06, Dimitri Szerman <dimitrijoe at ipea.gov.br> wrote:
> Dear all,
>
> I have a list with three (named) numeric vectors:
>
> > lst = list(a=c(A=1,B=8) , b=c(A=2,B=3,C=0), c=c(B=2,D=0) )
> > lst
> $a
> A B
> 1 8
>
> $b
> A B C
> 2 3 0
>
> $c
> B D
> 2 0
>
>
> Now, I'd love to use this list to create the following data frame:
>
> > dtf = data.frame(a=c(A=1,B=8,C=NA,D=NA),
> +                  b=c(A=2,B=3,C=0,D=NA),
> +                  c=c(A=NA,B=2,C=NA,D=0) )
>
> > dtf
>    a    b     c
> A   1   2  NA
> B   8   3     2
> C NA   0  NA
> D NA NA    0
>
> That is, I wish to "merge" the three vectors in the list into a data frame
> by their "(row)"names. Any suggestions? Thanks in advance for youR-Help.
>
> Dimitri
>
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>
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