[R] String manipulation and formatting

[Sean O'Riordain]

Does it have to be a stop char ".", or could it be a separate
parameter, i.e. put in a comma, then the 10 becomes an integer...

s/


On 18/07/06, Prof Brian Ripley <ripley at stats.ox.ac.uk> wrote:
> On Tue, 18 Jul 2006, Bashir Saghir (Aztek Global) wrote:
>
> > Thanks to Richard, Gabor and Marc for some nice solutions to my request.
> >
> > I have a new problem:
> >
> >   > xify(30.10)
> >   [1] "XXXXXXXXXXXXXXXXXXXXXXXXXXXXX.X"
> >   > xify(30.11)
> >   [1] "XXXXXXXXXXXXXXXXXXX.XXXXXXXXXXX"
> >
> > The problem originates from:
> >
> >   > as.numeric(unlist(strsplit(as.character(15.10), "\\.")))
> >   [1] 15  1
> >   > as.numeric(unlist(strsplit(as.character(15.11), "\\.")))
> >   [1] 15 11
> >
> > It seems to boils down to:
> >
> >   > as.character(15.10)
> >   [1] "15.1"
> >
> > A simple solution is:
> >
> >   > xify("15.10")
> >   [1] "XXXXX.XXXXXXXXXX"
> >
> > I was wondering if there is a simple way for xify to see the zero of the 10
> > without having to force the user to add quotes around the format?
>
> No, as the parser has converted '15.10' to a numeric constant.
>
> What is the problem with asking users to enter strings as strings?
>
> --
> Brian D. Ripley,                  ripley at stats.ox.ac.uk
> Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
> University of Oxford,             Tel:  +44 1865 272861 (self)
> 1 South Parks Road,                     +44 1865 272866 (PA)
> Oxford OX1 3TG, UK                Fax:  +44 1865 272595
>
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