[R] matrix matching NA

[Liaw, Andy]

Is this what you are looking for?

> m <- matrix(1:10, 5, 2)
> m[3, 1] <- m[5, 1] <- m[2, 2] <- NA
> m
     [,1] [,2]
[1,]    1    6
[2,]    2   NA
[3,]   NA    8
[4,]    4    9
[5,]   NA   10
> m[complete.cases(m),]
     [,1] [,2]
[1,]    1    6
[2,]    4    9

Andy 

From: Fabian Lienert
> 
> Dear R list members,
> 
> 
> I am seeking for an elegant way for matching NA elements of a matrix.
> Everthing I tried, the result was a vector.
> 
> Here ist an example with vectors that works:
> a and b are vectors of same lenght representing pairs of data (a[i]
> b[i]) with some NA elements:
> 
> ## R Code
> a <- (1:5)
> a[2] <- NA
> b <- (6:10)
> b[3] <- NA
> 
> a
>      1  NA  3  4  5
> b
>      6  7  NA  9 10
> ## /R Code
> 
> To get two vectors without any NA elements I do the following:
> 
> ## R Code
> awithoutan <- a[(1:length(a))[(!is.na(a))&(!is.na(b))]]
> bwithoutan <- b[(1:length(b))[(!is.na(a))&(!is.na(b))]]
> 
> awithoutan
>      1 4 5
> bwithoutan
>      6 9 10
> ## /R Code
> 
> How can I do the same matching in a matrix and get a matrix without NA
> elements (and less colums of course)?
> 
> matrix <- array(1:5*2, dim=c(5,2))
> matrix[,1] <- a
> matrix[,2] <- b
> matrix[,][(!is.na(matrix[,]))]
> 
> Gives me always a vector not a matrix.
> 
> 
> Thanks a lot for any hint,
> Fabian
> -- 
> Fabian Lienert, Climatology Student ETH Zurich, Switzerland
> 
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