[R] subsetting a matrix and filling other

[Christos Hatzis]

Use a list to store the partial matrices:

z <- vector("list", 189) 

for(i in 1:189)
	z[[i]] <- subset(...)

-Christos

-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of antonio rodriguez
Sent: Tuesday, November 07, 2006 2:01 PM
To: R-Help
Subject: [R] subsetting a matrix and filling other

Hi,

Having a matrix F(189,6575) I want to do this:

z1<-subset(F[,1], F[,1] >= 5 & F[,1] <= 10) .
.
.
z189<-subset(F[,189], F[,189] >= 5 & F[,189] <= 10)

I would prefer to have an empty matrix, say 'z' in order to fill its columns
with the output of subsetting F. But each of the subsets can differ in
length. It's to say:

length(z1)
1189

length(z2)
1238

Don't know how to set up this with a for loop or the use of apply:

z<-189
for (i in 1:189)
{z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}

Error in z[i] <- subset(F.zoo[, i], F.zoo[, i] >= 5 & z1 <= 10) :
        nothing to replace with

or

z<-matrix(0,6575,189)
for (i in 1:189)
{z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}

new error


Thanks,

Antonio

______________________________________________
R-help at stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.