[R] substitute values

Dimitris Rizopoulos dimitris.rizopoulos at med.kuleuven.be
Mon Apr 2 13:42:28 CEST 2007


if your data set is a matrix try this

new.data <- cbind(data, "New Column" = is.na(data[, "Years"]) & data[, 
"Products"] > 20)

whereas if your data set is a data.frame try this

data$"New.Column" <- as.numeric(is.na(data$Years) & data$Products > 
20)


I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
     http://www.student.kuleuven.be/~m0390867/dimitris.htm


----- Original Message ----- 
From: "Sergio Della Franca" <sergio.della.franca at gmail.com>
To: <r-help at stat.math.ethz.ch>
Sent: Monday, April 02, 2007 1:31 PM
Subject: [R] substitute values


> Dear R-Helpers,
>
> I have the following data set(y):
>
> Years   Products
> 1          10
> 2          25
> 3          40
> 4          NA
> 5          35
> <NA>   23
> 6         NA
> 7         67
> 8         NA
>
> I want to create a new column into my dataset(y) under the following
> conditions:
> if years =NA and products >20 then new column=1 else new column=0;
> to obtain the following results:
>
> Years   Products New Column
> 1          10          0
> 2          25          0
> 3          40          0
> 4          NA         0
> 5          35          0
> <NA>   23          1
> 6         NA          0
> 7         67           0
> 8         NA          0
>
> Thank you in advance.
>
>
> Serigo Della Franca
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 


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