# [R] Vectorize rearrangement within each column

Bill.Venables at csiro.au Bill.Venables at csiro.au
Fri Jan 19 09:00:05 CET 2007

```As with most things like this, you can trade memory for speed.  Here is
an obfuscated solution that appears to eschew loops entirely.

> ma <- matrix(10:15, nr = 3)
> idx <- matrix(c(1,3,2, 2,3,1), nr = 3)
> mb <- ma
> mb[] <- as.vector(ma)[as.vector(idx +
outer(rep(nrow(ma), nrow(ma)), 1:ncol(ma)-1, '*'))]
> mb
[,1] [,2]
[1,]   10   14
[2,]   12   15
[3,]   11   13

Ordinarily, though, my preferred solution would be the for() loop.

Bill Venables
CMIS, CSIRO Laboratories,
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-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Osorio Roberto
Sent: Friday, 19 January 2007 4:15 PM
To: r-help at stat.math.ethz.ch
Subject: [R] Vectorize rearrangement within each column

Consider a matrix like

> ma = matrix(10:15, nr = 3)
> ma
[,1] [,2]
[1,]   10   13
[2,]   11   14
[3,]   12   15

I want to rearrange each column according to row indexes (1 to 3)
given in another matrix, as in

> idx = matrix(c(1,3,2, 2,3,1), nr = 3)
> idx
[,1] [,2]
[1,]    1    2
[2,]    3    3
[3,]    2    1

The new matrix mb will have for each column the corresponding column
of ma indexed by the corresponding column of idx, as in

> mb = ma
> for (j in 1:2) mb[,j] = ma[idx[,j], j]
> mb
[,1] [,2]
[1,]   10   14
[2,]   12   15
[3,]   11   13

Can I avoid the for() loop? I'm specially interested to find out if a
fast implementation using lapply() would be feasible for large input
matrices (analogues of ma and idx) transformed into data frames.

Roberto Osorio

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