[R] Number of NA's in every second column

[Prof Brian Ripley]

On Sun, 20 May 2007, Dimitris Rizopoulos wrote:

> for data.frames try:
>
> rowSums(sapply(dfr, is.na))
>
> whereas for matrices you could use:
>
> rowSums(is.na(mat))

That will also work for a data frame (is.na on a data frame gives a 
matrix).  However, I think the poster wants (for X a data frame)

rowSums(is.na(X[, seq(1, ncol(x), by=2)])

or (more likelu given the strict interpretation of his English expression 
and of the subject line)

colSums[is.na(X[, seq(1, ncol(x), by=2)])

which could be done a bit more efficiently as

sapply(X[, seq(1, ncol(x), by=2)], function(x) sum(is.na(x)))


> I hope it helps.
>
> Best,
> Dimitris
>
> ----
> Dimitris Rizopoulos
> Ph.D. Student
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
>
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
> Web: http://med.kuleuven.be/biostat/
>      http://www.student.kuleuven.be/~m0390867/dimitris.htm
>
>
> Quoting Lauri Nikkinen <lauri.nikkinen at iki.fi>:
>
>> Hi R-users,
>>
>> How do I calculate a number of NA's in a row of every second column in my
>> data frame?
>>
>> As a starting point:
>> dfr <- data.frame(sapply(x, function(x) sample(0:x, 6, replace = TRUE)))
>> dfr[dfr==0] <- NA

That's not valid code: what is x?

>> So, I would like to count the number of NA in row one, two, three etc. of
>> columns X1, X3, X5 etc.
>>
>> Thanks in advance
>> Lauri
>>
>> 	[[alternative HTML version deleted]]
>>
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>
>
>
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-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272866 (PA)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595