[R] Dealing with NaN's in data frames

[Gabor Grothendieck]

Try this:

is.na(DF) <- is.na(DF)

or this which returns a transformed data frame without
overwriting DF:

replace(DF, is.na(DF), NA)

On Fri, Aug 15, 2008 at 10:27 PM, Peck, Jon <peck at spss.com> wrote:
> I am looking for the most efficient way to replace all occurrences of NaN in a data frame with NA.  I can do this with a double loop, but it seems that there should be a higher level and more efficient way.  With is.na, I could use ifelse, but if.nan seems not to have similar capabilities.
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> TIA,
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> Jon Peck
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> Jon K. Peck
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> jkpeck at aya.yale.edu
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