[R] bartlett.test()

Birgitle birgit.lemcke at systbot.uzh.ch
Thu Jun 5 11:33:20 CEST 2008

I think you should specify your grouping factor:

g   a vector or factor object giving the group for the corresponding
elements of x. Ignored if x is a list.

batlett.test(xx, groupingfactor)

Hope this helps.


hanen wrote:
> i'm trying to test the homogeneity of variance of 92 samples each one
> contains 3 observations.
> to use bartlett.test function i have created a (3,92) matrix (named xx):
> this message appears:
>>Erreur dans bartlett.test.default(xx) : 
>   l'argument "g" est manquant, avec aucune valeur par défaut
> when i checked the help i have understood that in g i should specified my
> différent samples in the case that xx is not a list.So i have tried to
> convert mode's xx in the list by:
> this message appears:
>>Erreur dans bartlett.test.default(list(xx)) : 
>   'x' must be a list with at least 2 elements
> what should i do?
> and if the solution is to use a data frame how can i add the 92
> columns'names to such data.frame? because the use of the function
> names(data.frame)<-list("...  and entering 92 words it seems painfull.
>  is there any one who can help me now?
> please answer me as soon as possible. 

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