[R] Which distribution best fits the data?
bolker at ufl.edu
Mon Jun 30 14:21:21 CEST 2008
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~ Much better.
~ If m is your linear regression model,
~ * boxcox(m) in the MASS package will look for a power (more or less)
transformation to normalize the residuals -- see the
book for more information
~ * plot(m) will produce plots including a Q-Q plot
(testing normality) of the residuals
~ * don't forget to check for autocorrelation in the
~ Ben Bolker
Jenny Barnes wrote:
| Hi Ben and R-help communtiy,
| More specifics:
| I am using sea-surface temperature (averaged over an area) and also
| winds (averaged over an area) to use in a linear regression model as
| predictors for rainfall over a small region of Africa. So I have 1 time
| series of sea-temp and one timeseries of rainfall (over 36 years -
| seasonal average) and I have performed the linear regression between the
| 2. I now want to check if the residuals are normally distributed. If
| they are not I want an R function that will tell me what distribution
| they are most similar to - so that I can apply a suitable transformation
| to make the data normal.....
| Any more tips now that you have a few more details perhaps? :o)
| Thanks for your time,
| On Mon, 30 Jun 2008, Ben Bolker wrote:
|> Jenny Barnes <jmb <at> mssl.ucl.ac.uk> writes:
|>> Dear R-help community,
|>> Does anybody know of a stats function in R that tells you which
|>> distribution best fits your data? I have tried look through the archives
|>> but have only found functions that tell you if it's normal or log etc.
|>> specifically - I am looking for a function that tells you (given a
|>> timeseries) what the distribution is.
|>> Any help/advice will be greatly appreciated,
|>> All the best,
|>> Jenny Barnes
|>> jmb <at> mssl.ucl.ac.uk
|> The problem is that it's not generally a good
|> idea to data-dredge in this way. Your best bet is
|> to think about the characteristics of the
|> data (discrete or continuous, non-negative or real,
|> symmetric or skewed) and try to narrow it down to
|> a few distributions -- then you can use fitdistr()
|> (from the MASS package) or something similar
|> to compare among them.
|> If you say a little bit more about what
|> you're trying to do with the data you might
|> get some more specific advice.
|> Ben Bolker
|> R-help at r-project.org mailing list
|> PLEASE do read the posting guide
|> and provide commented, minimal, self-contained, reproducible code.
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