[R] A very simple question

[Patrick Burns]

There have been several solutions like:

k[k != 3]

The more general form of this idea is:

k[!(k %in% 3)]

Sticking closer to the original form would be:

out <- which(k == 3)
if(length(out)) k[-out] else k


Patrick Burns
patrick at burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")

Shubha Vishwanath Karanth wrote:
> Hi R,
>
>  
>
> Suppose
>
> l=c(1,1,1,2,2,1,1,1)
>
>  
>
> k[-which(k==1)]
>
> [1] 2 2
>
>  
>
> k[-which(k==2)]
>
> [1] 1 1 1 1 1 1
>
>  
>
> But,
>
>  
>
> k[-which(k==3)]
>
> numeric(0)
>
>  
>
> I do not want this numeric(0), instead the whole k itself should be my
> result... How do I do this?
>
>  
>
>  
>
> Thanks,
>
> Shubha
>
>  
>
> This e-mail may contain confidential and/or privileged i...{{dropped:13}}
>
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