[R] sapply and median, possible or not ?

[Ptit_Bleu]

Hello,

I have a list of data.frame
rowsplit : List of 15
 $ (0,0.025]   :'data.frame':   169 obs. of  7 variables:
 $ (0.025,0.05]:'data.frame':   174 obs. of  7 variables:
 $ (0.05,0.075]:'data.frame':   92 obs. of  7 variables:
 $ (0.075,0.1] :'data.frame':   76 obs. of  7 variables:
 $ (0.1,0.125] :'data.frame':   37 obs. of  7 variables:
 $ (0.125,0.15]:'data.frame':   32 obs. of  7 variables:
 $ (0.15,0.175]:'data.frame':   45 obs. of  7 variables:
 $ (0.175,0.2] :'data.frame':   56 obs. of  7 variables:
 $ (0.2,0.225] :'data.frame':   36 obs. of  7 variables:
 $ (0.225,0.25]:'data.frame':   47 obs. of  7 variables:
 $ (0.25,0.275]:'data.frame':   34 obs. of  7 variables:
 $ (0.275,0.3] :'data.frame':   43 obs. of  7 variables:
 $ (0.3,0.325] :'data.frame':   29 obs. of  7 variables:
 $ (0.325,0.35]:'data.frame':   29 obs. of  7 variables:
 $ (0.35,0.375]:'data.frame':   17 obs. of  7 variables:

And I would like to get a data.frame gathering the median value of each
variable for each intervall.
as.data.frame(t(sapply(rowsplit, mean)) works well but I would prefer to use
median but with sapply(rowsplit, median), I get the following message "Error
in median.default(X[[1L]], ...) : need numeric data".

Any idea ?

Thanks in advance for your help,
Have a nice week-end,
Ptit Bleu.

PS :I'm under XP and use R2.7.2.  
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