[R] Programing and writing function help
erinm.hodgess at gmail.com
Wed Oct 8 12:55:53 CEST 2008
For all possible pairs, you'll have 20^2 pairs.
This is a way to do it:
On Wed, Oct 8, 2008 at 4:43 AM, Jim Lemon <jim at bitwrit.com.au> wrote:
> Stephen Cole wrote:
>> I have a vector of 20 values
>> x <- c(20,18, 45, 16, 47, 47, 15, 26, 14,14,12,16,35,27,18,94,16,26,26,30)
>> I want to select random pairs from this data set but do it without
>> replacement exhaustively
> then step through the columns of the resulting matrix
>> I know i can select random pairs without replacement using
>> However i am wondering if there is any way to get 10 random pairs from
>> data set without repeating any of the data points
>> that is to say if i got a (20, 94) for one pair, i would like to get 9
>> pairs from the data without again getting 20 or 94?
>> The second thing i would like to do is be able to select all possible
>> of numbers and calculate each pairs variance.
> I think you want to use the combn function, but you are going to get a lot
> of pairs...
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> and provide commented, minimal, self-contained, reproducible code.
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com
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