[R] (-8)^(1/3) == NaN?

[jim holtman]

It is the order of operator precedence.  Look at what you typed:

-8^1/3 is parsed as -(8^1)/3 = -2.66666

On Sun, Jul 19, 2009 at 1:12 PM, Victor Manuel Garcia
Guerrero<vmgarcia at colmex.mx> wrote:
> It' true, but if you type -8^(1/3) returns -2, and if you type -8^1/3 it returns -2.66666, maybe there are some rules about parenthesis...
>
> regards
>
> Víctor
>
>
> ________________________________
>
> De: r-help-bounces at r-project.org en nombre de Dave DeBarr
> Enviado el: sáb 18/07/2009 05:04
> Para: r-help at r-project.org
> Asunto: [R] (-8)^(1/3) == NaN?
>
>
>
> Why does the expression "(-8)^(1/3)" return NaN, instead of -2?
>
> This is not answered by http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-powers-of-negative-numbers-wrong_003f
>
> Thanks,
> Dave
>
>
>        [[alternative HTML version deleted]]
>
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>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

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