[R] regex expression to select row or column

[Junqian Gordon Xu]

Actually when I read the spreadsheet from cvs file, "S1-[abcd]" are the 
header and "T1-[abcd]" are the strings in first column of the data frame.

Gordon

On 07/25/2009 03:13 AM, jim holtman wrote:
> It it not entirely clear what the format of your data is. If you have
> a dataframe that you would like to separate into several different one
> based on the value in a column, then something like this will work:
> 
> df.list <- split(yourDF, yourDF$column)
> 
> This will create a list of dataframes, split according to the contents
> of "column".
> 
> On Fri, Jul 24, 2009 at 9:20 PM, Junqian Gordon Xu<xjqian at gmail.com> wrote:
>> I have a multidimensional data which looks like the following:
>>
>>       "S1-a" "S2-b" "S3-c" "S4-d" "S5-a" "S6-b" "S7-c" "S8-d"
>> "T1-A"
>> "T1-B"
>> "T1-C"
>> "T1-D"
>> "T2-A"
>> "T2-B"
>> "T2-C"
>> "T2-D"
>>
>> I read it from csv file and would like to have 16 separate data frames like
>> this
>>
>>     "S1-a" "S2-a"     "S1-b" "S2-b"     "S1-c" "S2-c"    "S1-d" "S2-d"
>> "T1-A"            "T1-A"            "T1-A"            "T1-A"
>> "T2-A"            "T2-A"            "T2-A"            "T2-A"
>>
>>     "S1-b" "S2-b"   ...
>> "T1-B"               ...
>> "T1-B"               ...
>>
>> ...
>> ...
>>
>> One way is to use loops to cycle through, but I think it's even simpler to
>> use regex expression to separate them since "abcd" and "ABCD" are unique
>> strings in the table. Does anybody have any pointer on how to do this?
>>
>> Thanks
>> Gordon