[R] Getting a column of values from a list - think I'm doing it thehard way

[ONKELINX, Thierry]

Dear Jason,

Have a look at years() from the chron package.

library(chron) 
HouseDates <- c("02/27/90", "02/27/91", "01/14/92", "02/28/93",
"02/01/94", "02/01/95", "02/01/96")
HouseDatesFormatted<-as.Date(HouseDates, "%m/%d/%y")
years(HouseDates)

HTH,

Thierry
------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
methodology and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
Thierry.Onkelinx at inbo.be
www.inbo.be

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than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey

-----Oorspronkelijk bericht-----
Van: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
Namens Jason Rupert
Verzonden: donderdag 4 juni 2009 4:45
Aan: R-help at r-project.org
Onderwerp: [R] Getting a column of values from a list - think I'm doing
it thehard way


Example code it shown below.

I think I am doing this the hard way.  I'm just trying to get the full
year value from an array of dates.  An example array is shown below.
Right now, I'm using a "for" loop to pull the year out of a list where
the dates were split up into their individual components.  

This seems to work, but just wondering if there is an easier way.  

Thanks for any insights. 

#*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~
HouseDates <- c("02/27/90", "02/27/91", "01/14/92", "02/28/93",
"02/01/94", "02/01/95", "02/01/96")

# ?as.Date
HouseDatesFormatted<-as.Date(HouseDates, "%m/%d/%y")

HouseDatesFormatted

HouseDatesList<-strsplit(as.character(HouseDatesFormatted), "-",
fixed=TRUE)

HouseYear_array<-NULL
length_array<-length(HouseDatesList)
for(ii in 1:length_array)
{   
        HouseYear<-HouseDatesList[[ii]][1]
        
        HouseYear_array<-c(HouseYear_array, HouseYear) }

as.character(HouseYear_array)

# Desired:
# [1] "1990" "1991" "1992" "1993" "1994" "1995" "1996"

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