[R] isolating Hour and minute form date and time

Gabor Grothendieck ggrothendieck at gmail.com
Wed Jun 10 13:27:46 CEST 2009


Try this and see R News 4/1 for more.

> now <- Sys.time(); now
[1] "2009-06-10 07:26:23 EDT"
> library(chron)
> ch <- as.chron(format(now))
> dd <- dates(ch); dd; dd+1
    day
06/10/09
    day
06/11/09
> tt <- times(ch) - times(dd); tt; tt+1/24
    day
07:26:23
    day
08:26:23

On Wed, Jun 10, 2009 at 7:13 AM, christiaan pauw<cjpauw at gmail.com> wrote:
> Hi everybody. I have a dataframe that contains a factor with the date
> information in the format like in the example below:
> "2009/05/12 11:22:31 AM"
>
> I have been able to convert it to POSIXt using strptime
>
> Now I want to print only the date as one vector and the time in another
> vector but they must be real date and time classes so that i can use them in
> calculations
>
> to reconstruct my situation:
>
> date=as.factor("2009/05/12 11:22:31 AM")
> posix.date=strptime(date, "%Y/%m/%d %I:%M:%S %p")
>
> I tried:
>
> time=format(posix.date, "%A %H:%M") # For weekday, hour and minute
>
> but the class in character. Now it prints like i want but it cannot be used
> in calculations.
>
> I would appreciate any suggestions
>
> Thanks in advance
> Christiaan
>
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>
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