[R] how to get all iterations if I meet NaN?

[Uwe Ligges]

huiming song wrote:
> hi, everybody, please help me with this question:
> 
> If I want to do iteration for 1000 times, however, for the 500th iteration,
> there is NaN appears. Then the iteration will stop. If I don't want the stop
> and want the all the 1000 iterations be done. What shall I do?
> 
> 
> suppose I have x[1:1000] and z[1:1000],I want to do some calculation for all
> x[1] to x[1000].
> 
> z=rep(0,1000)
> for (i in 1:1000){
>   z[i]=sin(1/x[i])
> }
> 
> if x[900] is 0, in the above code it will not stop when NaN appears. Suppose
> when sin(1/x[900]) is NaN appears and the iteration will now fulfill the
> rest 100 iterations. How can I write a code to let all the 1000 iterations
> be done?


See ?try

Uwe Ligges


> Thanks!
> 
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> 
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