[R] Why does aggregate fail?

David Winsemius dwinsemius at comcast.net
Sun Feb 7 19:32:38 CET 2010


You have a dataframe with 96 columns and a single row named "Sunday".  
My guess is that was not your intent. How did "d" come to exist?

-- 
David.

On Feb 7, 2010, at 1:29 PM, James Rome wrote:

>> dput(d)
> structure(list(`0` = 0, `1` = 1, `2` = 0, `3` = 0, `4` = 0, `5` = 0,
>    `6` = 0, `7` = 0, `8` = 0, `9` = 0, `10` = 0, `11` = 0, `12` = 0,
>    `13` = 0, `14` = 0, `15` = 0, `16` = 0, `17` = 2, `18` = 0,
>    `19` = 0, `20` = 0, `21` = 0, `22` = 0, `23` = 0, `24` = 0,
>    `25` = 0, `26` = 0, `27` = 0, `28` = 0, `29` = 0, `30` = 0,
>    `31` = 0, `32` = 5, `33` = 5, `34` = 5, `35` = 0, `36` = 0,
>    `37` = 0, `38` = 0, `39` = 0, `40` = 0, `41` = 0, `42` = 6,
>    `43` = 0, `44` = 3, `45` = 1, `46` = 0, `47` = 1, `48` = 6,
>    `49` = 8, `50` = 9, `51` = 7, `52` = 9, `53` = 10, `54` = 5,
>    `55` = 0, `56` = 1, `57` = 0, `58` = 1, `59` = 1, `60` = 1,
>    `61` = 0, `62` = 0, `63` = 0, `64` = 1, `65` = 0, `66` = 0,
>    `67` = 7, `68` = 10, `69` = 9, `70` = 9, `71` = 11, `72` = 11,
>    `73` = 8, `74` = 8, `75` = 10, `76` = 7, `77` = 6, `78` = 7,
>    `79` = 8, `80` = 7, `81` = 4, `82` = 4, `83` = 6, `84` = 5,
>    `85` = 5, `86` = 5, `87` = 5, `88` = 0, `89` = 0, `90` = 0,
>    `91` = 1, `92` = 6, `93` = 2, `94` = 3, `95` = 0), .Names = c("0",
> "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12",
> "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23",
> "24", "25", "26", "27", "28", "29", "30", "31", "32", "33", "34",
> "35", "36", "37", "38", "39", "40", "41", "42", "43", "44", "45",
> "46", "47", "48", "49", "50", "51", "52", "53", "54", "55", "56",
> "57", "58", "59", "60", "61", "62", "63", "64", "65", "66", "67",
> "68", "69", "70", "71", "72", "73", "74", "75", "76", "77", "78",
> "79", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89",
> "90", "91", "92", "93", "94", "95"), row.names = "Sunday", class =
> "data.frame")
> On 2/7/2010 1:27 PM, David Winsemius wrote:
> On Feb 7, 2010, at 1:08 PM, James Rome wrote:
>
>> I am trying to get hourly totals, given 15-minute bins.
>> s = seq(0, 95, 1)
>> s = floor(s/4)   # 0  0  0  0  1  1  1  1  2  2  2  2  3  3  3  3   
>> 4 .
>> . .
>>
>>> s
>> [1]  0  0  0  0  1  1  1  1  2  2  2  2  3  3  3  3  4  4  4  4  5  5
>> 5  5  6
>> [26]  6  6  6  7  7  7  7  8  8  8  8  9  9  9  9 10 10 10 10 11 11  
>> 11
>> 11 12 12
>> [51] 12 12 13 13 13 13 14 14 14 14 15 15 15 15 16 16 16 16 17 17 17  
>> 17
>> 18 18 18
>> [76] 18 19 19 19 19 20 20 20 20 21 21 21 21 22 22 22 22 23 23 23 23
>>
>>> mode(d)
>> [1] "list"
>>> d
>>      0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
>> 25 26
>> Sunday 0 1 0 0 0 0 0 0 0 0  0  0  0  0  0  0  0  2  0  0  0  0  0   
>> 0  0
>> 0  0
>>      27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47  
>> 48
>> 49 50
>> Sunday  0  0  0  0  0  5  5  5  0  0  0  0  0  0  0  6  0  3  1  0  1
>> 6  8  9
>>      51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71  
>> 72
>> 73 74
>> Sunday  7  9 10  5  0  1  0  1  1  1  0  0  0  1  0  0  7 10  9  9 11
>> 11  8  8
>>      75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95
>> Sunday 10  7  6  7  8  7  4  4  6  5  5  5  5  0  0  0  1  6  2  3  0
>>> x = aggregate(d, by=list(s), FUN="sum")
>> Error in FUN(X[[1L]], ...) : arguments must have same length
>
> I don't know what sort of error is occurring. You have not created a
> posting that easily lets us see what sort of object "d" really is.  
> (And
> it is not being display as though it were a simple list.)
>
> dput(d) would have allowed us to see what sort of attributes it has.
> Your code works if one strips out the data and puts it into a vector.
>
>> s = seq(0, 95, 1)
>> s = floor(s/4)
>
>> d <- scan()
> 1: 0 1 0 0 0 0 0 0 0 0  0  0  0  0  0  0  0  2  0  0  0  0  0  0  0
> 26: 0  0
> 28: 0  0  0  0  0  5  5  5  0  0  0  0  0  0  0  6  0  3  1  0  1
> 49: 6  8  9
> 52: 7  9 10  5  0  1  0  1  1  1  0  0  0  1  0  0  7 10  9  9 11
> 73: 11  8  8
> 76: 10  7  6  7  8  7  4  4  6  5  5  5  5  0  0  0  1  6  2  3  0
> 97:
> Read 96 items
>> x = aggregate(d, by=list(s), FUN="sum")
>> x
>   Group.1  x
> 1        0  1
> 2        1  0
> 3        2  0
> 4        3  0
> 5        4  2
> 6        5  0
> 7        6  0
> 8        7  0
> 9        8 15
> 10       9  0
> 11      10  6
> 12      11  5
> 13      12 30
> 14      13 24
> 15      14  3
> 16      15  1
> 17      16  8
> 18      17 39
> 19      18 37
> 20      19 28
> 21      20 21
> 22      21 20
> 23      22  1
> 24      23 11
>
>>> length(s)
>> [1] 96
>>> length(d)
>> [1] 96
>>
>> What am I doing wrong?
>>
>> Thanks in advance list,
>> Jim Rome
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> David Winsemius, MD
> Heritage Laboratories
> West Hartford, CT
>
>

David Winsemius, MD
Heritage Laboratories
West Hartford, CT



More information about the R-help mailing list