[R] Row-wisely converting a data frame into a list

[David Winsemius]

On Mar 2, 2010, at 8:11 AM, Sebastian Bauer wrote:

> Hello,
>
> is there an elegant way, how I can convert each row of a data frame  
> into distinct elements of a list?

split(dfrm, rownames(dfrm))

>
> In essence, what I'm looking for is something like
>
> rows.to.lists <- function( df ) {
> 	ll <- NULL
> 	for( i in 1:nrow(df) )
> 		ll <- append( ll, list(df[i,]) )
> 	return (ll)
> }
>
> but more done more efficiently (the data frame may contain ten- 
> thousands of rows). I thought about using apply() but this function  
> always returns a matrix.
>
> Thanks in advance!
>
> Bye,
> Sebastian
>
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