[R] Setting the names of a data.frame

[Ivan Calandra]

Hi,

The problem is that all your columns of sHeaders are factors. It might 
be better to set stringsAsFactors to FALSE when you build it.

Or you can do it with a for loop like this:
for (i in 1:length(sHeaders)){
  names(tData)[i] <- as.character(sHeaders[1,i])
}

Or with lapply:
names(tData) <- unlist(lapply(sHeaders[1, ], FUN=as.character))

HTH,
Ivan

Le 11/2/2010 14:58, Santosh Srinivas a écrit :
> I have tData as below. I need to set the names with the headers from the
> first row in sHeaders
> Sorry .. forgot how to set the names from row in another data frame .. pls
> advise.
>
> names(tData) = sHeaders[1,] does not work correctly
>
> Also, why doesn't drop.levels(sHeaders) not work?
>
> dput(tData)
> structure(list(V1 = structure(c(3L, 1L, 1L, 2L), .Label = c("P H Ravi
> Kumar",
> "Rahul Kumar Singh", "Ramu GSV"), class = "factor"), V2 = structure(c(1L,
> 3L, 3L, 2L), .Label = c("05/10/2010", "09/09/2010", "30/09/2010"
> ), class = "factor"), V3 = structure(c(2L, 1L, 1L, 2L), .Label = c("B",
> "S"), class = "factor"), V4 = structure(c(2L, 3L, 3L, 1L), .Label =
> c("2120",
> "4000", "11000"), class = "factor"), V5 = structure(c(1L, 2L,
> 2L, 1L), .Label = c("", "0.01"), class = "factor"), V6 = structure(c(2L,
> 3L, 3L, 1L), .Label = c("765", "1000", "11000"), class = "factor"),
>      V7 = structure(c(1L, 2L, 2L, 1L), .Label = c("", "0.01"), class =
> "factor")), .Names = c("V1",
> "V2", "V3", "V4", "V5", "V6", "V7"), row.names = 5:8, class = "data.frame")
>
>
> dput(sHeaders)
> structure(list(V1 = structure(1L, .Label = c("Name of Acquirer / Seller",
> "Qty", "Ramu GSV"), class = "factor"), V2 = structure(3L, .Label =
> c("05/10/2010",
> "%", "Transaction Date"), class = "factor"), V3 = structure(1L, .Label =
> c("Buy /Sale",
> "Qty", "S"), class = "factor"), V4 = structure(3L, .Label = c("4000",
> "%", "No.of Shares Transacted"), class = "factor"), V5 = structure(2L,
> .Label = c("",
> "Holding after Transaction"), class = "factor"), V6 = structure(NA_integer_,
> .Label = "1000", class = "factor"),
>      V7 = structure(NA_integer_, .Label = "", class = "factor")), .Names =
> c("V1",
> "V2", "V3", "V4", "V5", "V6", "V7"), row.names = 3L, class = "data.frame")
>
>
> Thanks very  much.
>
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-- 
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. Säugetiere
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calandra at uni-hamburg.de

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