[R] is there a way to avoid "traveling" grid?

ONKELINX, Thierry Thierry.ONKELINX at inbo.be
Tue Oct 5 17:28:43 CEST 2010


Dear Dimitri,

Ggplot2 solves your problem with the gridlines and requires much less
code. You only need to reshape your data somewhat.

library(ggplot2)
#changing the dataset
my.data2 <- my.data
my.data2$x <- my.data$x + my.data$a
my.data2$z <- my.data$y + my.data$z
Molten2 <- melt(my.data2, id.vars = "date")
Molten2$variable <- factor(Molten2$variable, levels = c("z", "y", "x",
"a"))

#basic plot
ggplot(Molten2, aes(x = date, y = value, fill = variable)) + 
	geom_area(position = "identity")

#changing the lay-out a bit
ggplot(Molten2, aes(x = date, y = value, fill = variable)) + 
	geom_area(position = "identity") + 
	scale_fill_manual(value = c(z = "orange", y = "green", x =
"blue", a = "yellow")) + 
	scale_x_date(major = "months", format="%d-%m-%Y") + 
	opts(axis.text.x = theme_text(angle = 90, hjust = 1))

HTH,

Thierry

------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium

Research Institute for Nature and Forest
team Biometrics & Quality Assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium

tel. + 32 54/436 185
Thierry.Onkelinx op inbo.be
www.inbo.be

To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey
  

> -----Oorspronkelijk bericht-----
> Van: r-help-bounces op r-project.org 
> [mailto:r-help-bounces op r-project.org] Namens Dimitri Liakhovitski
> Verzonden: dinsdag 5 oktober 2010 16:37
> Aan: r-help op r-project.org
> Onderwerp: [R] is there a way to avoid "traveling" grid?
> 
> Hello!
> 
> If you run the whole code below, it'll produce a stacked diagram. And
> it looks good - because the tick-marks are aligned with the grid.
> However, if I stretch the graph window, grid becomes misaligned with
> the tickmarks. Or, rather, it seems aligned for the first and the last
> tick mark, but not for tickmarks in between.
> Can it be addressed?
> Thank you!
> 
> Dimitri
> 
> 
> ### Creating a data set with both positives and negatives
> my.data<-data.frame(date=c(20080301,20080401,20080501,20080601
,20080701,20080801,20080901,20081001,20081101,20081201,20090101,20090201
,20090301,20090401,20090501,20090601,20090701,20090801,20090901,20091001
,20091101,20091201,> 20100101,20100201,20100301,20100402,20100503),
> x=c(1.1, 1, 1.6, 1, 2, 1.5, 2.1, 1.3, 1.9, 1.1, 1, 1.6, 1, 2, 1.5,
> 2.1, 1.3, 1.9, 1.1, 1, 1.6, 1, 2, 1.5, 2.1, 1.3, 1.9),
> y=c(-4,-3,-6,-5,-7,-5.2,-6,-4,-4.9,-4,-3,-6,-5,-7,-5.2,-6,-4,-
> 4.9,-4,-3,-6,-5,-7,-5.2,-6,-4,-4.9),
> z=c(-0.2,-0.3,-0.4,-0.1,-0.2,-0.05,-0.2,-0.15,-0.06,-0.2,-0.3,
> -0.4,-0.1,-0.2,-0.05,-0.2,-0.15,-0.06,-0.06,-0.2,-0.3,-0.4,-0.
> 1,-0.2,-0.05,-0.2,-0.15),
> a=c(10,13,15,15,16,17,15,16,14,10,13,15,15,16,17,15,16,14,10,1
> 3,15,15,16,17,15,16,14))
> my.data$date<-as.character(my.data$date)
> my.data$date<-as.Date(my.data$date,"%Y%m%d")
> (my.data)
> str(my.data)
> 
> positives<-which(colSums(my.data[2:ncol(my.data)])>0) # which vars
> have positive column sums?
> negatives<-which(colSums(my.data[2:ncol(my.data)])<0) # which vars
> have negative column sums?
> 
> y.max<-1.1*max(rowSums(my.data[names(positives)])) # the max on the y
> axis of the chart
> y.min<-1.1*min(rowSums(my.data[names(negatives)])) # the min on the y
> axis of the chart
> ylim <- c(y.min, y.max)
> order.positives<-rev(rank(positives))
> order.of.pos.vars<-names(order.positives)
> order.negatives<-rev(rank(negatives))
> order.of.neg.vars<-names(order.negatives)
> order<-c(order.negatives,order.positives)
> order.of.vars<-names(order)   # the order of variables on the chart -
> from the bottom up
> ### so, the bottom-most area should be for z, the second from the
> bottom area- for y (above z)
> 
> all.colors<-c('red','blue','green','orange','yellow','purple')
> xx <- c(my.data$date, rev(my.data$date))
> bottom.y.coordinates<-rowSums(my.data[names(negatives)])
> 
> 
> par(mar=c(5,4,4,6),xpd=F)
> plot(x=my.data$date, y=bottom.y.coordinates, ylim=ylim, col='white',
> type='l', xaxt='n',
> 	ylab='Title for Y', xlab="", main='Chart Title')
> 
> for(var in order.of.neg.vars){
> 	top.line.coords<-bottom.y.coordinates-my.data[[var]]
> 	bottom.coords<-c(bottom.y.coordinates,rev(top.line.coords))
> 	
> polygon(xx,bottom.coords,col=all.colors[which(names(my.data) 
> %in% var)])
> 	bottom.y.coordinates<-top.line.coords
> }
> 
> for(var in order.of.pos.vars){
> 	top.line.coords<-bottom.y.coordinates+my.data[[var]]
> 	bottom.coords<-c(bottom.y.coordinates,rev(top.line.coords))
> 	
> polygon(xx,bottom.coords,col=all.colors[which(names(my.data) 
> %in% var)])
> 	bottom.y.coordinates<-top.line.coords
> }
> 
> axis(1, labels =format(as.Date(my.data$date, origin="1970-01-01"),
> "%Y-%m-%d"), at=my.data$date, las=2,cex.axis=0.7)
> grid(nx=(length(my.data$date)-1),ny=NULL,col = "lightgray", lty =
> "dotted",lwd = par("lwd"))
> 
> legend(par()$usr[2],
>   mean(par()$usr[3:4]),
>   c("Blue","Yellow","Green","Orange"),
>   xpd=T,
>   bty="n",
>   pch=12,
>   col=c("Blue","Yellow","Green","Orange"))
> 
> ______________________________________________
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> PLEASE do read the posting guide 
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> and provide commented, minimal, self-contained, reproducible code.
> 

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