[R] Chron object in time series plot

[Phil Spector]

The following will create a POSIXlt object using the current date:

> strptime(sprintf('%06d',breaks),'%H%M%S')
  [1] "2010-10-19 07:00:00" "2010-10-19 07:15:00" "2010-10-19 07:30:00"
  [4] "2010-10-19 07:45:00" "2010-10-19 08:00:00" "2010-10-19 08:15:00"
  [7] "2010-10-19 08:30:00" "2010-10-19 08:45:00" "2010-10-19 09:00:00"
                       . . .

To get just the hours and minutes, you could use

> format(strptime(sprintf('%06d',breaks),'%H%M%S'),'%H:%M')
  [1] "07:00" "07:15" "07:30" "07:45" "08:00" "08:15" "08:30" "08:45" "09:00"
[10] "09:15" "09:30" "09:45" "10:00" "10:15" "10:30" "10:45" "11:00" "11:15"
                      . . .

And I'm still not sure I've answered your question.

 					- Phil Spector
 					 Statistical Computing Facility
 					 Department of Statistics
 					 UC Berkeley
 					 spector at stat.berkeley.edu



On Tue, 19 Oct 2010, Manta wrote:

>
> I do not think that importing the time as character will help me, as I need
> to perform several operation with them. Again, maybe I am not able to
> express clearly enough. Let's just focus on this series:
>
>> breaks
> [1]  70000  71500  73000  74500  80000  81500  83000  84500  90000  91500
> 93000  94500 100000 101500 103000 104500
> [17] 110000 111500 113000 114500 120000 121500 123000 124500 130000 131500
> 133000 134500 140000 141500 143000 144500
> [33] 150000 151500 153000 154500 160000 161500 163000 164500 170000 171500
> 173000 174500 180000 181500 183000 184500
>
> I want a simple function that can convert breaks into a treatable object by
> 'zoo' as follows:
>
> [1] 07:00 07:15 07:30 ....
> ..
> [33]...
> 18:00 18:15 18:30 18:45
>
> Is this possible?
> -- 
> View this message in context: http://r.789695.n4.nabble.com/Chron-object-in-time-series-plot-tp3002285p3002458.html
> Sent from the R help mailing list archive at Nabble.com.
>
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