[R] taking rows from data.frames in list to form new data.frame?

[jctoll]

Hi,

I am having a problem figuring out how to extract a subset of rows.  I
have a list with 68 similar data.frames.  Each data.frame is 500 rows
by 5 columns.  I want to take one row from each data.frame based upon
the data in a particular column (i.e. it matches a symbol).  For
example:

> str(database)
List of 68
 $ X2011.01.11:'data.frame':	500 obs. of  5 variables:
  ..$ Symbol    : chr [1:500] "MMM" "ACE" "AES" "AFL" ...
  ..$ Price     : num [1:500] 87.7 60.7 13.1 55.7 15.6 ...
  ..$ Shares.Out: num [1:500] 7.15e+08 3.39e+08 7.88e+08 4.71e+08 1.10e+08 ...
  ..$ Float     : num [1:500] 7.13e+08 3.38e+08 6.61e+08 4.60e+08 1.09e+08 ...
  ..$ Market.Cap: num [1:500] 6.27e+10 2.06e+10 1.04e+10 2.62e+10 1.72e+09 ...
 $ X2011.01.12:'data.frame':	500 obs. of  5 variables:
  ..$ Symbol    : chr [1:500] "MMM" "ACE" "AES" "AFL" ...
  ..$ Price     : num [1:500] 88.7 60.9 12.9 57.1 15.2 ...
  ..$ Shares.Out: num [1:500] 7.15e+08 3.39e+08 7.88e+08 4.71e+08 1.10e+08 ...
  ..$ Float     : num [1:500] 7.13e+08 3.38e+08 6.61e+08 4.60e+08 1.09e+08 ...
  ..$ Market.Cap: num [1:500] 6.34e+10 2.06e+10 1.02e+10 2.69e+10 1.68e+09 ...
 . . .

> lapply(database, function(x) which(x == "IBM"))
$X2011.01.11
[1] 234

$X2011.01.12
[1] 234
 . . .

> lapply(database, function(x) x[which(x == "IBM"), ])
$X2011.01.11
    Symbol  Price Shares.Out    Float Market.Cap
234    IBM 147.28   1.24e+09 1.24e+09 1.8297e+11

$X2011.01.12
    Symbol Price Shares.Out    Float Market.Cap
234    IBM 149.1   1.24e+09 1.24e+09 1.8524e+11
 . . .

What I would like to do is create a new data.frame with 68 rows by 5
columns of data, perhaps using the old data.frame names as the new
row.names. I can get to the subset of data that I want, I just can't
get it from list form into one new data.frame.  Any suggestions?
Thank you.

James