sarah.goslee at gmail.com
Fri Dec 9 20:24:18 CET 2011
>From the bottom of every email on this list:
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
And from the posting guide:
Basic statistics and classroom homework: R-help is not intended for these.
I'm not sure how being from your lab professor makes it any less applicable.
On Fri, Dec 9, 2011 at 2:17 PM, <gauthiergabrielle at yahoo.com> wrote:
> This actually is my homework from my lab professor, although I applaud her rude assumptions
> Sent from my Verizon Wireless BlackBerry
> -----Original Message-----
> From: Sarah Goslee <sarah.goslee at gmail.com>
> Date: Fri, 9 Dec 2011 14:12:01
> To: Gabrielle Gauthier<gauthiergabrielle at yahoo.com>
> Cc: <r-help at r-project.org>
> Subject: Re: [R] HELP
> On Fri, Dec 9, 2011 at 1:35 PM, Gabrielle Gauthier
> <gauthiergabrielle at yahoo.com> wrote:
>> I was wondering if anyone could help me with my R homework.
> This list is not for doing homework, though I applaud your honesty in
> admitting it.
> Your instructor is being paid to teach you; that's who you should be
> consulting, rather than asking people on this list to help you cheat.
> Good luck,
> I have using the R tutorials and help options but it just is not
> helping me at all. I have some questions completed but these are the
> ones i need help on:
>> A.) Plot the values in vector MyNumbers in a scatterplot. B.) Create a new vector named NewNumbers, with values equal to four times those in MyNumbers plus a random number chosen from a normal distribution with mean 5 and standard deviation 3. C.) Plot MyNumbers against NewNumbers in a scatterplot. Find the slope and intercept using a linear model. Find out how much of the variance is due to your fit, and how much is due to the residuals.
>> A.) An IQ test is normally distributed with a mean of 100 and a standard deviation of 15. n What score would be needed to be in the 95th percentile? B.) In what percentile would the score 112 fall? C.) What is the probability of getting a score that is exactly the mean?
>> We measured test scores in 3 conditions, no studying, desperate studying, and studying well. There were 6 people in each condition. Perform an ANOVA on the data, with readable output, by doing the following: A.) Create a vector of these conditions (independent variable vector) that treats them as a factor. B.) No studying had mean 65 and standard deviation 8, desperate studying had mean 78 and standard deviation 3, and studying well had mean 90 and standard deviation 1. Create random data based on this information, and place it in a variable. C.) Perform an ANOVA on the data, with readable output.
>> If anyone could help that would be greatly appreciated!!
More information about the R-help