[R] Ordering a matrix based on cluster no

[Aparna Sampath]

Thanks for the help! But when I tried it, it does not work the same way I
want. :(
 after combining the two matrices, they look like this:


             V1            V2               X           TEL.AML1.C41  
Hyperdip.50.C23
1     TEL.AML1.C41   1    TEL.AML1.C41       1.0000000      0.00000000
2  Hyperdip.50.C23   1    Hyperdip.50.C23    0.0000000      1.00000000
3       BCR.AB.LC1    1    BCR.AB.LC1           0.1212121      0.78125000
4  Hyperdip.50.C13   1    Hyperdip.50.C13    0.0000000      1.00000000
6       TEL.AML1.9    1    T.ALL.C5              0.0000000      0.03225807
7       TEL.AML1.8    1    TEL.AML1.9          1.0000000      0.00000000
8   Hyperdip.50.C7    1   TEL.AML1.8           1.0000000      0.00000000
9     TEL.AML1.C37   1   Hyperdip.50.C7       0.0000000      1.00000000
11    TEL.AML1.C47  1   TEL.AML1.C37        1.0000000      0.00000000
13  Hyperdip.50.11   1   MLL.6                    0.0000000      0.03225807


when i do :  orddata1  <- df2_a[order(df2_a[,1],decreasing=T),] 

I get the result:

           V1           V2                   X           TEL.AML1.C41
Hyperdip.50.C23
22   TEL.AML1.C49   1       TEL.AML1.2M.1            1          0.00000000
11   TEL.AML1.C47   1       TEL.AML1.C37              1         0.00000000
1    TEL.AML1.C41   1        TEL.AML1.C41             1          0.00000000
9    TEL.AML1.C37   1        Hyperdip.50.C7            0          1.00000000
6    TEL.AML1.9      1        T.ALL.C5                     0        
0.03225807
7    TEL.AML1.8      1        TEL.AML1.9                 1        
0.00000000
16  TEL.AML1.2M.4  1        Hyperdip.50.11            0         1.00000000
19  TEL.AML1.2M.1  1        TEL.AML1.2M.4            1         0.00000000
15  Hyperdip.50.R2  1        T.ALL.C10                   0        
0.00000000
20  Hyperdip.50.C9  1        BCR.ABL.Hyperdip.R5     0         1.00000000


The results are not right! I want it to look for the gene TEL.AML1.C49 in
the second matrix and group it accordingly. 

Aparna 

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