[R] Create a matrix with increment and element with zero subscript

[Joshua Wiley]

Hi Deana,

No, R does not deal with zero subscripts.  Could it be done?  Of
course.  The simplest approach is: 0 + 1 = 1, which is the R
equivalent.  You need to adjust your code to go, for example, from 1
to 30 instead of 0 to 29.

Cheers,

Josh

On Mon, Oct 24, 2011 at 4:23 PM, Md Desa, Zairul Nor Deana Binti
<zndeana at ku.edu> wrote:
> Hello,
> Does anyone knows how to deal with zero subscript in R. I have this code:
> for (i in 1:nitems){
> +             for (j in 1:ncat-1)  {
> +          draw<-matrix(rnorm(nitems*(ncat-1),seed1,seed2),nitems,(ncat-1))
> +          d<-( sigma_d*draw ) + mu_d
> +         draw<-matrix(rtnorm((nitems*(ncat-1)),mean = seed1, sd = seed2, lower = .1, upper = 1.5),nitems,(ncat-1))
> +           d<-(sigma_d*draw) + mu_d
> +           write.matrix(cbind(b.i0,d), file = "F:/KU/MIRT group/MIMIC-DIF/R/cpprcode/b0d.dat", sep = "  ")
> +             b[i,j]<-b[i,j-1]+d[i,j]
> +                }
> +             }
>
> The error as following:
>
> Error in b[i, j ] <- b[i, j - 1] + d[i, j] :
>  replacement has length zero
>
> I would like to to have a matrix where the first column takes from initial pre-assigned value (b[i,0]+d1), the second column is additive from the first column and a constant d2 that is (b(i,1)=b(i,0)+d1+d2, and so forth. Is there any way that R can read subscript of zero?
>
> Thanks,
> Deana
>
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-- 
Joshua Wiley
Ph.D. Student, Health Psychology
Programmer Analyst II, ATS Statistical Consulting Group
University of California, Los Angeles
https://joshuawiley.com/