[R] Trim

[arun]

Hi,
I guess with only one rev() should also work:
 idx<-cumsum(!is.na(dat$V2))*rev(cumsum(!is.na(dat$V2)))!=0
 dat[idx,]
#       V1        V2
#3 2006-10 0.1577647
#4 2006-11       NaN
#5 2006-12       NaN
#6 2007-01       NaN
#7 2007-02       NaN
#8 2007-03 0.2956429
A.K.


----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: Vasilchenko Aleksander <vasilchenko.a.p at gmail.com>
Cc: r-help at r-project.org
Sent: Wednesday, December 5, 2012 7:59 AM
Subject: Re: [R] Trim

Hello,

Try the following.

dat <-
structure(list(V1 = structure(c(2L, 3L, 1L, 2L, 3L, 4L, 5L, 6L,
4L, 5L), .Label = c("2006-10", "2006-11", "2006-12", "2007-01",
"2007-02", "2007-03"), class = "factor"), V2 = c(NaN, NaN, 0.1577647,
NaN, NaN, NaN, NaN, 0.2956429, NaN, NaN)), .Names = c("V1", "V2"
), class = "data.frame", row.names = c("1", "2", "3", "4", "5",
"6", "7", "8", "9", "10"))

idx <- cumsum(!is.nan(dat$V2)) * rev(cumsum(rev(!is.nan(dat$V2)))) != 0
dat[idx, ]


Hope this helps,

Rui Barradas
Em 05-12-2012 10:46, Vasilchenko Aleksander escreveu:
> Hello,
> I have a dataframe
>
> 1 2006-11       NaN
> 2 2006-12       NaN
> 3 2006-10 0.1577647
> 4 2006-11       NaN
> 5 2006-12       NaN
> 6 2007-01       NaN
> 7 2007-02       NaN
> 8 2007-03 0.2956429
> 9 2007-01       NaN
> 10 2007-02       NaN
> I need to trim first and last NaN rows
> Result -
> 1 2006-10 0.1577647
> 2 2006-11       NaN
> 3 2006-12       NaN
> 4 2007-01       NaN
> 5 2007-02       NaN
> 6 2007-03 0.2956429
> Thanks.
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.