[R] Writing a function to return column position XXXX

R. Michael Weylandt michael.weylandt at gmail.com
Tue Jan 24 15:04:21 CET 2012


Either

any(grepl("$",x, fixed = TRUE)) # You probably want grepl not grep
any(grepl("\\$",x) )
? regexpr # $ has a special value

Michael

PS -- Stop with HTML postings (seriously, it actually does mess up
what the rest of us see and I think it causes trouble for the archives
as well)

On Tue, Jan 24, 2012 at 8:49 AM, Dan Abner <dan.abner99 at gmail.com> wrote:
> Hello everyone,
>
> I am writing my own function to return the column index of all variables
> (these are currently character vectors) in a data frame that contain a
> dollar sign($). A small piece of the data look like this:
>
>    can_sta can_zip ind_ite_con ind_uni_con AL 36106 $251,895.80 $22,874.43
> AL 35802 $141,373.60 $7,100.00  AL 35201 $273,208.50 $18,193.66  AR
> 72404 $186,918.00
> $25,391.00  AR 72217 $451,127.00 $27,255.23  AR 7.28E+08 $58,336.22 $5,293.82
>
>
> So far I have:
>
>
> col.id<-function(x) any(grep("$",x))
> sapply(cand2,col.id)
>
> However, this returns TRUE for all columns (even those that do not contain
> the $).
>
> Any assistance is appreciated.
>
> Thank you,
>
> Dan
>
>        [[alternative HTML version deleted]]
>
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