[R] add leading zeros

R. Michael Weylandt michael.weylandt at gmail.com
Fri Jul 27 06:54:34 CEST 2012


Much easier than you think:

x <- c(1L, 9000L)

sprintf("%05i",x)

Best,
Michael

On Thu, Jul 26, 2012 at 8:08 PM, LCOG1 <jroll at lcog.org> wrote:
> Hi all,
>      Trying to use an apply to add leading zeros to a set of values in a
> given vector.  I only want to add enough zeros so that the total number of
> characters is 5, so if I have an element "1" i want "00001" or "9000" I want
> "09000".  I tried
>
> vec <- 1:1000
> sapply(vec, FUN = sprintf(paste("%0",(5-nchar(x)),"d",sep=""),x))
>
> but she doesnt work.  I struggle with the apply family for sure.  Thanks
>
> Josh
>
>
>
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