[R] caret: Error when using rpart and CV != LOOCV

Dominik Bruhn dominik at dbruhn.de
Thu May 17 19:35:54 CEST 2012


Hy Max,
thanks again for the answer.

I checked the caret implementation and you were right. If the
predictions for the model constant (or sd(pred)==0) then the
implementation returns a NA for the rSquare (in postResample). This is
mainly because the caret implementation uses `cor` (from the
stats-package) which would throw a error for values with sd(pred)==0.

Do you know why this is implemented in this way? I wrote my own
summaryFunction which calculates rSquare by hand and it works fine. It
nevertheless does NOT(!) generate the same values as the original
implementation. It seems that the calcuation of Rsquare does not seem to
be consistent. I took mine from Wikipedia [1].

Here is my code:
---
customSummary <- function (data, lev = NULL, model = NULL) {
         #Calulate rSquare
         ssTot <- sum((data$obs-mean(data$obs))^2)
         ssErr <- sum((data$obs-data$pred)^2)
         rSquare <- 1-(ssErr/ssTot)

         #Calculate MSE
         mse <- mean((data$pred - data$obs)^2)

         #Aggregate
         out <- c(sqrt(mse), 1-(ssErr/ssTot))
         names(out) <- c("RMSE", "Rsquared")

         return(out)
}
---

[1]: http://en.wikipedia.org/wiki/Coefficient_of_determination#Definitions

Thanks!
Dominik




On 17/05/12 04:10, Max Kuhn wrote:
> Dominik,
> 
> See this line:
> 
>>   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
>>  30.37   30.37   30.37   30.37   30.37   30.37
> 
> The variance of the predictions is zero. caret uses the formula for
> R^2 by calculating the correlation between the observed data and the
> predictions which uses sd(pred) which is zero. I believe that the same
> would occur with other formulas for R^2.
> 
> Max
> 
> On Wed, May 16, 2012 at 11:54 AM, Dominik Bruhn <dominik at dbruhn.de> wrote:
>> Thanks Max for your answer.
>>
>> First, I do not understand your post. Why is it a problem if two of
>> predictions match? From the formula for calculating R^2 I can see that
>> there will be a DivByZero iff the total sum of squares is 0. This is
>> only true if the predictions of all the predicted points from the
>> test-set are equal to the mean of the test-set. Why should this happen?
>>
>> Anyway, I wrote the following code to check what you tried to tell:
>>
>> --
>> library(caret)
>> data(trees)
>> formula=Volume~Girth+Height
>>
>> customSummary <- function (data, lev = NULL, model = NULL) {
>>    print(summary(data$pred))
>>    return(defaultSummary(data, lev, model))
>> }
>>
>> tc=trainControl(method='cv', summaryFunction=customSummary)
>> train(formula, data=trees,  method='rpart', trControl=tc)
>> --
>>
>> This outputs:
>> ---
>>  Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
>>  18.45   18.45   18.45   30.12   35.95   53.44
>>   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
>>  22.69   22.69   22.69   32.94   38.06   53.44
>>   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
>>  30.37   30.37   30.37   30.37   30.37   30.37
>> [cut many values like this]
>> Warning: In nominalTrainWorkflow(dat = trainData, info = trainInfo,
>> method = method,  :
>>  There were missing values in resampled performance measures.
>> -----
>>
>> As I didn't understand your post, I don't know if this confirms your
>> assumption.
>>
>> Thanks anyway,
>> Dominik
>>
>>
>> On 16/05/12 17:30, Max Kuhn wrote:
>>> More information is needed to be sure, but it is most likely that some
>>> of the resampled rpart models produce the same prediction for the
>>> hold-out samples (likely the result of no viable split being found).
>>>
>>> Almost every incarnation of R^2 requires the variance of the
>>> prediction. This particular failure mode would result in a divide by
>>> zero.
>>>
>>> Try using you own summary function (see ?trainControl) and put a
>>> print(summary(data$pred)) in there to verify my claim.
>>>
>>> Max
>>>
>>> On Wed, May 16, 2012 at 11:30 AM, Max Kuhn <mxkuhn at gmail.com> wrote:
>>>> More information is needed to be sure, but it is most likely that some
>>>> of the resampled rpart models produce the same prediction for the
>>>> hold-out samples (likely the result of no viable split being found).
>>>>
>>>> Almost every incarnation of R^2 requires the variance of the
>>>> prediction. This particular failure mode would result in a divide by
>>>> zero.
>>>>
>>>> Try using you own summary function (see ?trainControl) and put a
>>>> print(summary(data$pred)) in there to verify my claim.
>>>>
>>>> Max
>>>>
>>>> On Tue, May 15, 2012 at 5:55 AM, Dominik Bruhn <dominik at dbruhn.de> wrote:
>>>>> Hy,
>>>>> I got the following problem when trying to build a rpart model and using
>>>>> everything but LOOCV. Originally, I wanted to used k-fold partitioning,
>>>>> but every partitioning except LOOCV throws the following warning:
>>>>>
>>>>> ----
>>>>> Warning message: In nominalTrainWorkflow(dat = trainData, info =
>>>>> trainInfo, method = method, : There were missing values in resampled
>>>>> performance measures.
>>>>> -----
>>>>>
>>>>> Below are some simplified testcases which repoduce the warning on my
>>>>> system.
>>>>>
>>>>> Question: What does this error mean? How can I avoid it?
>>>>>
>>>>> System-Information:
>>>>> -----
>>>>>> sessionInfo()
>>>>> R version 2.15.0 (2012-03-30)
>>>>> Platform: x86_64-pc-linux-gnu (64-bit)
>>>>>
>>>>> locale:
>>>>>  [1] LC_CTYPE=en_GB.UTF-8       LC_NUMERIC=C
>>>>>  [3] LC_TIME=en_GB.UTF-8        LC_COLLATE=en_GB.UTF-8
>>>>>  [5] LC_MONETARY=en_GB.UTF-8    LC_MESSAGES=en_GB.UTF-8
>>>>>  [7] LC_PAPER=C                 LC_NAME=C
>>>>>  [9] LC_ADDRESS=C               LC_TELEPHONE=C
>>>>> [11] LC_MEASUREMENT=en_GB.UTF-8 LC_IDENTIFICATION=C
>>>>>
>>>>> attached base packages:
>>>>> [1] stats     graphics  grDevices utils     datasets  methods   base
>>>>>
>>>>> other attached packages:
>>>>> [1] rpart_3.1-52   caret_5.15-023 foreach_1.4.0  cluster_1.14.2
>>>>> reshape_0.8.4
>>>>> [6] plyr_1.7.1     lattice_0.20-6
>>>>>
>>>>> loaded via a namespace (and not attached):
>>>>> [1] codetools_0.2-8 compiler_2.15.0 grid_2.15.0     iterators_1.0.6
>>>>> [5] tools_2.15.0
>>>>> -------
>>>>>
>>>>>
>>>>> Simlified Testcase I: Throws warning
>>>>> ---
>>>>> library(caret)
>>>>> data(trees)
>>>>> formula=Volume~Girth+Height
>>>>> train(formula, data=trees,  method='rpart')
>>>>> ---
>>>>>
>>>>> Simlified Testcase II: Every other CV-method also throws the warning,
>>>>> for example using 'cv':
>>>>> ---
>>>>> library(caret)
>>>>> data(trees)
>>>>> formula=Volume~Girth+Height
>>>>> tc=trainControl(method='cv')
>>>>> train(formula, data=trees,  method='rpart', trControl=tc)
>>>>> ---
>>>>>
>>>>> Simlified Testcase III: The only CV-method which is working is 'LOOCV':
>>>>> ---
>>>>> library(caret)
>>>>> data(trees)
>>>>> formula=Volume~Girth+Height
>>>>> tc=trainControl(method='LOOCV')
>>>>> train(formula, data=trees,  method='rpart', trControl=tc)
>>>>> ---
>>>>>
>>>>>
>>>>> Thanks!
>>>>> --
>>>>> Dominik Bruhn
>>>>> mailto: dominik at dbruhn.de
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> ______________________________________________
>>>>> R-help at r-project.org mailing list
>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>
>>>>
>>>>
>>>>
>>>> --
>>>>
>>>> Max
>>>
>>>
>>>
>>
>>
>> --
>> Dominik Bruhn
>> mailto: dominik at dbruhn.de
>>
> 
> 
> 


-- 
Dominik Bruhn
mailto: dominik at dbruhn.de

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