[R] Presence/ absence data from matrix to single column
ruipbarradas at sapo.pt
Sun Oct 7 20:32:51 CEST 2012
I haven't been following this thread but apparently the answer to your
worries is no.
You can use a combination of names() and grep() to sort it out.
#nms <- names(adat)
nms <- c("Year", "Route", "Point", paste0("Sp", 1:250))
pattern <- "^Sp[[:digit:]]+$"
whichCols <- grep(pattern, nms)
whichNames <- nms[whichCols]
reshape(..., varying = whichCols, times = whichNames, ...)
Hope this helps,
Em 07-10-2012 15:35, agoijman escreveu:
> The problem with that, is that I just wrote an example of my database, but I
> have around 250 species and more than 500 sites. In the approach you show
> me, it looks like I have to enter every species name and sites individually,
> View this message in context: http://r.789695.n4.nabble.com/Presence-absence-data-from-matrix-to-single-column-tp4645271p4645331.html
> Sent from the R help mailing list archive at Nabble.com.
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> and provide commented, minimal, self-contained, reproducible code.
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