[R] How to use tapply with more than one variables grouped
smartpink111 at yahoo.com
Tue Oct 23 22:08:45 CEST 2012
I think I understand what you meant. This will output all those states where contribution for Obama is higher than all the other candidates.
AL AR CA NY
Doug 250 250 250 NA
Jennifer 20 340 300 100
Michele 250 500 250 60
Obama 15 45 520 600
res<-unlist(lapply(apply(dat1,2,function(x) x[!is.na(x)]),function(x) x[all(x["Obama"]>x[names(x)!=names(x)[grep("Obama",names(x))]])]))
# 520 600
----- Original Message -----
From: noobmin <pseudovoid at hotmail.com>
To: r-help at r-project.org
Sent: Tuesday, October 23, 2012 3:00 PM
Subject: Re: [R] How to use tapply with more than one variables grouped
I meant where obama has higher value compared to other candidates. Looking at
the column NY, Obama has the highest. So to state that he wins. Looking for
AR column, Michelle wins. I JUST want to list where obama wins.
Thank you! This seems to work, just do not understand why you used a
I will study your solution, thanks again!
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